Worked example
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Specific electrical power
kW/(m³/min)
- Specific power in imperial units
- kW/100 cfm
- Flow in m³/min
- 16.7 m³/min
- Flow in cfm
- cfm
- Flow per electrical kW
- 0.167 m³/min per kW
Compare only at aligned pressure, flow reference conditions, system boundary and time interval.
Underlined figures are rounded. Select one to copy its full value.
Method and assumptions
Formula
specific energy = complete electrical input kW ÷ delivered flowFlow-unit conversion does not reconcile standard, normal, free-air-delivery or actual operating conditions.
Limits of this result
- Compare values only at an aligned discharge pressure and the same flow reference conditions.
- Include package auxiliaries, dryers and other system loads only when the comparison boundary requires them and state that boundary.
- A short steady-state ratio does not represent annual system efficiency, leakage or production effectiveness.
Technical sources
Put the value to work
Read the related engineering guidance, or carry this task into System Builder to identify the signal path and EpiSensor products.