Worked example
No result for these values. The message above the form says which field to change.
Secondary line current, each line
A
- Primary line current, each line
- A
- Apparent power at the entered loading
- 100 kVA
- Voltage ratio, primary to secondary
- 27.5 :1
Three-phase, line-to-line voltages. The entered loading is within the nameplate kVA; permissible duty remains manufacturer-specific.
Underlined figures are rounded. Select one to copy its full value.
Method and assumptions
Formula
1φ: I = kVA × 1000 ÷ V; 3φ: I = kVA × 1000 ÷ (√3 × VLL)Rated kVA is apparent power, so power factor and efficiency are not used to calculate nominal winding current from the nameplate rating.
Limits of this result
- This calculates nominal line current from apparent-power loading; it does not model losses, inrush, harmonics or unbalance.
- Voltage taps, vector group, cooling, impedance, protection and loading duty remain transformer-specific.
- Do not use this result alone to size or protect a transformer or conductor.
Technical sources
Put the value to work
Read the related engineering guidance, or carry this task into System Builder to identify the signal path and EpiSensor products.